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x^2-7.46x-45=0
a = 1; b = -7.46; c = -45;
Δ = b2-4ac
Δ = -7.462-4·1·(-45)
Δ = 235.6516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.46)-\sqrt{235.6516}}{2*1}=\frac{7.46-\sqrt{235.6516}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.46)+\sqrt{235.6516}}{2*1}=\frac{7.46+\sqrt{235.6516}}{2} $
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